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There are currently no product reviews.
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thanks a lot.
without the service manual my handycam was going to the trash.
good job, go on.
bye
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This service manual is a good copy of the original, complete and fully readable. It is really useful to repair my Tv set following its clear instructions.
 ;
Excellent quality. Easy process to download. No issues or problems at all - was exactly what I was looking for and needed. Great service.
 ;
I was having a hard time finding the problem with this Mackie 1604 unit. I didn't have a schematic. Went looking on the web and found your site and the price was more then reasonable. Ordered it and within the hour had the manual and within 15 minutes had the unit fixed. Best $4.99 I ever spent. Thank you.
Doug
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This is a service manual in every sense of the word ( French and German versions of the text are included, as well as English..)
There are explanations of the mechanical and electrical functions, plenty of mechanical drawings, and the needed schematics. The quality of the scanning is excellent - all the component values are clearly legible - and very usefully there are pcb component layouts, so you can find a component on the schematic, and then very quicky pinpoint its physical location on the relevant pcb.
I cannot see how I can give this manual any less than the maximum 5 stars! Great value for money, which will pay for itself immediately. Excellent all round!
Performance Tests Output Standing Wave Ratio (SWR) Test
thermistor mount that can be operated at two different resistances and can accurately measure the power absorbed. The thermistor mount type Agilent 478A with option H75 or option H76 normally operates at a DC resistance of 200� giving an impedance at RF of 50� and �L close to zero. When the thermistor bridge is set to 100� the RF impedance is 25� giving a nominal � L of 0.33. The effective efficiency of the thermistor mount remains constant under these two conditions so that the power ratio between operation at 200� and 100� can be accurately measured. If the two reflection coefficients are �1 and �2 and these give the power measurements of P1 and P2 respectively (but the available power remains the same) then the two relationships can be equated as follows: Equation 2-6:
P1
1 � �s �1 1 � �s �2 --------------------------- = P --------------------------1 � �1
2 2
2
2
1 � �2
2
Where: Therefore: Equation 2-7:
2 P 1 ( 1 � �2 2 ) 1 � �s �2 ------ ------------------------- = -------------------------P2 ( 1 � � 2) 1�� � 2 1 s1
Where: The left side of the equation can be replaced by the factor M as follows: Equation 2-8:
1 � �s �2 M = -------------------------1 � �s �1
2
2
Where: This cannot be directly solved for �S because it is a complex quantity. In order to solve for � S additional values of load reflection coefficient are required with a phase difference of approximately 120o. However an approximate solution using two values of �L can give adequately accurate results provided the phase angle of the source is within ±40o of 0o or ±180o.
Agilent E4416A/E4417A Service Guide
2-29
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